Regex

CODE SNIPET

String regex “\s”;
String input = "Testing the text for regex";
String replace = ”Text to be replaced”;

Pattern pattern = Pattern.compile(regex);
Matcher matcher = pattern.matcher(input);

if(matcher.find()){
   ...
}

Other Functions
Matcher.matches() – returns true or false
Input  = m.replaceAll(replace);

CODE

import java.util.regex.Matcher;
import java.util.regex.Pattern;

public class RegexTestPatternMatcher {
  public static final String EXAMPLE_TEST = "This is my small example string which I'm going to use for pattern matching.";

  public static void main(String[] args) {
    Pattern pattern = Pattern.compile("\\w+");
    Matcher matcher = pattern.matcher(EXAMPLE_TEST);
    // check all occurance
    while (matcher.find()) {
      System.out.print("Start index: " + matcher.start());
      System.out.print(" End index: " + matcher.end() + " ");
    }
  }
}

OR

import java.util.regex.Matcher;
import java.util.regex.Pattern;

public class RegexMatches
{
    public static void main( String args[] ){

      // String to be scanned to find the pattern.
      String line = "This order was placed for QT3000! OK?";
      String pattern = "(.*)(\\d+)(.*)";

      // Create a Pattern object
      Pattern r = Pattern.compile(pattern);

      // Now create matcher object.
      Matcher m = r.matcher(line);
      if (m.find( )) {
         System.out.println("Found value: " + m.group(0) );
         System.out.println("Found value: " + m.group(1) );
         System.out.println("Found value: " + m.group(2) );
      } else {
         System.out.println("NO MATCH");
      }
   }
}